A tuning fork vibrates with a frequency of 440 hertz (cycles/second). When the tuning fork is struck, it produces a change in the normal air pressure in the room.

Function p represents this situation, where
is the change in pressure, in pascals, relative to the normal air pressure in the room as a function of time, t, in seconds, after the tuning fork is struck.

What are the domain and the range within the context of this situation?

1 answer

In the context of the situation described with the tuning fork vibrating and producing changes in air pressure, let's analyze the domain and range of the function p(t), which represents the change in pressure in pascals over time t in seconds.

Domain: The domain is the set of all possible values of t for which the function p(t) is defined. Since we are examining the pressure change over time after the tuning fork is struck, the time t begins at 0 seconds (the moment the tuning fork is struck) and extends indefinitely. Thus, the domain can be expressed as:

  • Domain: t0, or in interval notation: [0,).

Range: The range is the set of all possible values of p(t). The change in pressure caused by the tuning fork's vibrations can fluctuate above and below the normal air pressure. The pressure changes typically oscillate around 0 pascals, as they represent deviations from the normal air pressure. The changes can be positive (increased pressure) or negative (decreased pressure).

Given that tuning forks produce sinusoidal oscillations, the range of p(t) would encompass all possible values resulting from these oscillations, confined typically to a maximum and minimum amplitude. However, without specific amplitude information, we consider that pressure change might oscillate above and below zero:

  • Range: All real numbers within the amplitude achieved by the tuning fork, usually expressed as (A,A) where A is the maximum amplitude of pressure change (the actual values depend on the specific characteristics of the tuning fork and its environment).

In summary:

  • Domain: [0,) (time in seconds after the tuning fork is struck)
  • Range: (A,A) (change in pressure in pascals, where A is the maximum amplitude)
Similar Questions
  1. Type the correct answer in each box. Use numerals instead of words.A tuning fork vibrates with a frequency of 440 hertz
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 2 answers
  2. 3.A 512 Hz tuning fork and a 1024 Hz tuning fork are struck with a hammer of the same intensity. How will the sound waves
    1. answers icon 1 answer
more similar questions