9/4 is close to the square root of what integer?(1 point).

1 answer

First, let's calculate the approximate value of \( \frac{9}{4} \):

\[ \frac{9}{4} = 2.25 \]

Next, we want to find the square root of an integer that is close to \( 2.25 \). To do this, we can find the perfect squares around 2.25.

The square of 1 is:

\[ 1^2 = 1 \]

The square of 2 is:

\[ 2^2 = 4 \]

Since \( 2.25 \) is between \( 1 \) and \( 4 \), we look for an integer whose square root is approximately \( 2.25 \). The number whose square root is closest to \( 2.25 \) is \( 5 \), because:

\[ \sqrt{5} \approx 2.236 \]

Therefore, \( 2.25 \) is close to the square root of the integer \( 5 \).

Thus, \( \frac{9}{4} \) is close to the square root of the integer \( \boxed{5} \).