Let's simplify the original expression step by step:
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The expression is \( \frac{1}{2}(9−7^0)+(−29)^0 \).
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First, calculate \( 7^0 \) and \( (-29)^0 \):
- Any non-zero number raised to the power of 0 is 1, so \( 7^0 = 1 \) and \( (-29)^0 = 1 \).
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Substitute these values back into the expression: \[ \frac{1}{2}(9−1) + 1 \]
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Now simplify \( 9 - 1 = 8 \): \[ \frac{1}{2}(8) + 1 \]
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Calculate \( \frac{1}{2}(8) = 4 \): \[ 4 + 1 = 5 \]
So the simplified version of the original expression is \( 5 \).
Now let's check each response to see which one is equivalent to the simplified expression.
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\( \frac{1}{2}(9−1)+1 \):
- \( 9 - 1 = 8 \), then \( \frac{1}{2}(8) + 1 = 4 + 1 = 5 \).
- This is equivalent.
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\( \frac{1}{2}(2)+1 \):
- \( \frac{1}{2}(2) + 1 = 1 + 1 = 2 \).
- This is not equivalent.
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\( \frac{1}{2}(9−0)+0 \):
- \( 9 - 0 = 9 \), then \( \frac{1}{2}(9) + 0 = 4.5 + 0 = 4.5 \).
- This is not equivalent.
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\( \frac{1}{2}(9−1)−1 \):
- \( 9 - 1 = 8 \), then \( \frac{1}{2}(8) - 1 = 4 - 1 = 3 \).
- This is not equivalent.
The only equivalent expression is:
\( \frac{1}{2}(9−1)+1 \).