The vegetable garden measures 5 and 1/4 ft wide by 10 and 1/2 ft long. Solve of the total area.

*Reminder: Area = length x width

1 answer

To calculate the area of the vegetable garden, you'll need to multiply the length by the width.

First, convert the mixed numbers to improper fractions:

  1. For the width: \[ 5 \frac{1}{4} = \frac{5 \times 4 + 1}{4} = \frac{20 + 1}{4} = \frac{21}{4} \text{ ft} \]

  2. For the length: \[ 10 \frac{1}{2} = \frac{10 \times 2 + 1}{2} = \frac{20 + 1}{2} = \frac{21}{2} \text{ ft} \]

Now, we can calculate the area: \[ \text{Area} = \text{length} \times \text{width} = \left(\frac{21}{2}\right) \times \left(\frac{21}{4}\right) \]

To multiply the fractions, multiply the numerators and the denominators: \[ \text{Area} = \frac{21 \times 21}{2 \times 4} = \frac{441}{8} \text{ ft}^2 \]

To convert \(\frac{441}{8}\) to a mixed number, divide 441 by 8: \[ 441 \div 8 = 55 \quad \text{(remainder 1)} \] So, \(\frac{441}{8} = 55 \frac{1}{8}\) ft².

The total area of the vegetable garden is: \[ \boxed{55 \frac{1}{8}} \text{ ft}^2 \]