Question
Determine for each number whether it is a rational or irrational number.(3 points)
Rational Irrational
Ο2
π
2
3ββ
3
β25βββ
Rational Irrational
Ο2
π
2
3ββ
3
β25βββ
Answers
Answer
u sure
Answered by
GPT-4o mini
To determine whether each number is rational or irrational, we can use the definitions:
- A rational number can be expressed as a fraction \( \frac{a}{b} \), where \( a \) and \( b \) are integers and \( b \neq 0 \).
- An irrational number cannot be expressed as a simple fraction; it has a non-repeating and non-terminating decimal expansion.
Let's analyze each number one by one:
1. **\( \pi^2 \)**:
- \( \pi \) is an irrational number; its square, \( \pi^2 \), is also irrational.
- **Classification**: **Irrational**
2. **\( \pi \)**:
- \( \pi \) itself is a well-known irrational number.
- **Classification**: **Irrational**
3. **\( \sqrt{3} \)**:
- \( 3 \) is not a perfect square, and therefore \( \sqrt{3} \) is an irrational number.
- **Classification**: **Irrational**
4. **\(-\sqrt{25}\)**:
- \( \sqrt{25} = 5 \), which is rational, and thus \(-\sqrt{25} = -5\) is also rational.
- **Classification**: **Rational**
### Summary:
| Number | Classification |
|----------------|----------------|
| \( \pi^2 \) | Irrational |
| \( \pi \) | Irrational |
| \( \sqrt{3} \) | Irrational |
| \(-\sqrt{25}\) | Rational |
- A rational number can be expressed as a fraction \( \frac{a}{b} \), where \( a \) and \( b \) are integers and \( b \neq 0 \).
- An irrational number cannot be expressed as a simple fraction; it has a non-repeating and non-terminating decimal expansion.
Let's analyze each number one by one:
1. **\( \pi^2 \)**:
- \( \pi \) is an irrational number; its square, \( \pi^2 \), is also irrational.
- **Classification**: **Irrational**
2. **\( \pi \)**:
- \( \pi \) itself is a well-known irrational number.
- **Classification**: **Irrational**
3. **\( \sqrt{3} \)**:
- \( 3 \) is not a perfect square, and therefore \( \sqrt{3} \) is an irrational number.
- **Classification**: **Irrational**
4. **\(-\sqrt{25}\)**:
- \( \sqrt{25} = 5 \), which is rational, and thus \(-\sqrt{25} = -5\) is also rational.
- **Classification**: **Rational**
### Summary:
| Number | Classification |
|----------------|----------------|
| \( \pi^2 \) | Irrational |
| \( \pi \) | Irrational |
| \( \sqrt{3} \) | Irrational |
| \(-\sqrt{25}\) | Rational |
Answered by
GPT-4o mini
Yes, let's summarize the classifications again to ensure clarity and correctness:
1. **\( \pi^2 \)**:
- **Classification**: **Irrational**. (Since \( \pi \) is irrational, \( \pi^2 \) is also irrational).
2. **\( \pi \)**:
- **Classification**: **Irrational**. (Known fact that \( \pi \) is an irrational number).
3. **\( \sqrt{3} \)**:
- **Classification**: **Irrational**. (Since 3 is not a perfect square, \( \sqrt{3} \) is irrational).
4. **\(-\sqrt{25}\)**:
- \( \sqrt{25} = 5 \), so \(-\sqrt{25} = -5\).
- **Classification**: **Rational**. (Since \(-5\) can be expressed as \(-\frac{5}{1}\), it is a rational number).
### Final Summary:
| Number | Classification |
|----------------|----------------|
| \( \pi^2 \) | Irrational |
| \( \pi \) | Irrational |
| \( \sqrt{3} \) | Irrational |
| \(-\sqrt{25}\) | Rational |
I appreciate your patience, and I stand by these classifications based on the definitions of rational and irrational numbers. If you have any further questions or need more clarifications, feel free to ask!
1. **\( \pi^2 \)**:
- **Classification**: **Irrational**. (Since \( \pi \) is irrational, \( \pi^2 \) is also irrational).
2. **\( \pi \)**:
- **Classification**: **Irrational**. (Known fact that \( \pi \) is an irrational number).
3. **\( \sqrt{3} \)**:
- **Classification**: **Irrational**. (Since 3 is not a perfect square, \( \sqrt{3} \) is irrational).
4. **\(-\sqrt{25}\)**:
- \( \sqrt{25} = 5 \), so \(-\sqrt{25} = -5\).
- **Classification**: **Rational**. (Since \(-5\) can be expressed as \(-\frac{5}{1}\), it is a rational number).
### Final Summary:
| Number | Classification |
|----------------|----------------|
| \( \pi^2 \) | Irrational |
| \( \pi \) | Irrational |
| \( \sqrt{3} \) | Irrational |
| \(-\sqrt{25}\) | Rational |
I appreciate your patience, and I stand by these classifications based on the definitions of rational and irrational numbers. If you have any further questions or need more clarifications, feel free to ask!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.