How many of the following equations have the solution set {5} ? 2(x−3)+1=5 3b15=1 2h−30=40 (1 point) The number of equations that have the solution set {5} is

To determine how many of the given equations have the solution set {5}, we need to solve each equation individually and check if it yields the solution \( x = 5 \).

1. **Equation 1: \( 2(x - 3) + 1 = 5 \)**

\[
2(x - 3) + 1 = 5
\]
\[
2(x - 3) = 5 - 1
\]
\[
2(x - 3) = 4
\]
\[
x - 3 = \frac{4}{2}
\]
\[
x - 3 = 2
\]
\[
x = 2 + 3
\]
\[
x = 5
\]

This equation has the solution \( x = 5 \).

2. **Equation 2: \( 3b = 15 \)**

\[
3b = 15
\]
\[
b = \frac{15}{3}
\]
\[
b = 5
\]

This equation has the solution \( b = 5 \).

3. **Equation 3: \( 2h - 30 = 40 \)**

\[
2h - 30 = 40
\]
\[
2h = 40 + 30
\]
\[
2h = 70
\]
\[
h = \frac{70}{2}
\]
\[
h = 35
\]

This equation does not have the solution \( h = 5 \).

Now, let's summarize the findings:

- **Equation 1:** Has \( x = 5 \)
- **Equation 2:** Has \( b = 5 \)
- **Equation 3:** Does not have \( h = 5 \)

Therefore, **2 out of the 3 equations** have the solution set {5}.

The number of equations that have the solution set {5} is **2**.