Graph the function y = -1/2x^2+4

1 answer

To graph the function \( y = -\frac{1}{2}x^2 + 4 \), we can follow these steps:

Step 1: Identify the shape of the graph

The function is a quadratic equation in the form \( y = ax^2 + bx + c \). Here, \( a = -\frac{1}{2} \), meaning the parabola opens downward.

Step 2: Find the vertex

The vertex form of a parabola is obtained from the standard form by completing the square or can be found using the formula for the x-coordinate of the vertex:

\[ x = -\frac{b}{2a} \]

In this function, \( b = 0 \) (since there is no \( x \) term) and \( a = -\frac{1}{2} \):

\[ x = -\frac{0}{2 \times -\frac{1}{2}} = 0 \]

Now, substitute \( x = 0 \) back into the equation to find \( y \):

\[ y = -\frac{1}{2}(0)^2 + 4 = 4 \]

Thus, the vertex of the parabola is \( (0, 4) \).

Step 3: Find the x-intercepts

To find the x-intercepts, set \( y = 0 \):

\[ 0 = -\frac{1}{2}x^2 + 4 \]

Rearranging gives:

\[ \frac{1}{2}x^2 = 4 \] \[ x^2 = 8 \] \[ x = \pm \sqrt{8} = \pm 2\sqrt{2} \]

The x-intercepts are approximately \( x \approx 2.83 \) and \( x \approx -2.83 \).

Step 4: Find the y-intercept

The y-intercept occurs when \( x = 0 \):

\[ y = -\frac{1}{2}(0)^2 + 4 = 4 \]

Thus, the y-intercept is at \( (0, 4) \).

Step 5: Select additional points

To get a better shape of the parabola, we can choose a few values around the vertex to find corresponding y-values:

  • For \( x = 2 \): \[ y = -\frac{1}{2}(2^2) + 4 = -\frac{1}{2}(4) + 4 = -2 + 4 = 2 \]

  • For \( x = -2 \): \[ y = -\frac{1}{2}(-2^2) + 4 = -\frac{1}{2}(4) + 4 = -2 + 4 = 2 \]

Step 6: Graph the points

You can plot the following points:

  • Vertex: \( (0, 4) \)
  • X-intercepts: \( (2\sqrt{2}, 0) \) and \( (-2\sqrt{2}, 0) \) (approximately \( (2.83, 0) \) and \( (-2.83, 0) \))
  • Y-intercept: \( (0, 4) \)
  • Additional points: \( (2, 2) \) and \( (-2, 2) \)

Step 7: Draw the parabola

Using these points, sketch the graph of the parabola, making sure it opens downward. The graph will have a symmetrical shape about the y-axis due to the absence of an x term.

If you have graphing software or a graphing calculator, you can input the equation directly to visualize the parabola accurately. However, the key points and features mentioned will guide you in manually sketching the graph.

Similar Questions
  1. UserYou The graph of a quadratic function is shown. Which statement appears to be true? The function has 3 zeros The maximum
    1. answers icon 1 answer
  2. The graph of a quadratic function is shown.Which statement appears to be true? The function has 3 zeros. The maximum value of
    1. answers icon 1 answer
  3. The function g(x) = x2 is transformed to obtain function h:h(x) = g(x) + 1. Which statement describes how the graph of h is
    1. answers icon 1 answer
  4. Which statement describes the graph of function g compared to function f?f(x) = 6x − 2 g(x) = 0.4(6)x − 2 A. The graph of g
    1. answers icon 1 answer
more similar questions