Asked by Anonymous

A sample of silver with a mass of 63.3g is heated to a temperature of 384.4 K and placed in a container water at 290.0K The final temperature of the silver and water is 292.4K assuming no heat loss, what mass of water was in the container? the specific heat of water is 4.184J/(g.C) and of silver 0.24J/(g.C)
Answered by DrBob222
[mass water x specific heat water x (Tfinal-Tinitial)] + [mass Ag x specific heat Ag x (Tfinal-Tinitial) = 0
Solve for Tfinal.
Answered by Anonymous
139.8
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