Question

Vertical line segment upper M upper P is plotted on a coordinate plane. The x-axis ranges from negative 1 to 3 and the y-axis ranges from negative 7 to 7 both in 1 unit increments.
Q is the midpoint of line segment PM. Find the midpoint Q.

(1 point)
Responses

Q is located at (1,0)
Q is located at (1,0)

Q is located at (0.5,0)
Q is located at (0.5,0)

Q is located at (1,6)
Q is located at (1,6)

Q is located at (1,-6)

Answer 1

To find the midpoint \( Q \) of the vertical line segment \( PM \), we need the coordinates of points \( P \) and \( M \). However, these coordinates are not provided in your question.

In general, the midpoint \( Q \) of a line segment with endpoints \( P(x_1, y_1) \) and \( M(x_2, y_2) \) can be calculated using the midpoint formula:

\[
Q\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)
\]

Since this is a vertical line segment, the x-coordinates of \( P \) and \( M \) will be the same. Thus, if we assume the x-coordinate is \( a \), and the y-coordinates of \( P \) and \( M \) are \( y_1 \) and \( y_2 \) respectively, the midpoint coordinates would be:

\[
Q\left(a, \frac{y_1 + y_2}{2}\right)
\]

If you happen to provide the exact coordinates of points \( P \) and \( M \), I can calculate the coordinates of midpoint \( Q \) for you.