Question

Fill in the blanks!
Using the standard Method to Multiply a Two-Digit Number by a One-Digit Number
Find the product of 22 x 3
Write it vertically. The number with more digits goes on top, and the _ values should be lined up.

22
x3
----
___

Now, write the problem in expanded form.
(20 + _) x 3
(20 x _) + (2x3)
_+6
66

Answer 1

Let's fill in the blanks step-by-step.

1. We start with the multiplication set up vertically:
```
22
x 3
-----
```

2. The blank under the line will be filled with the product of 22 and 3. Now, let's perform the multiplication.

3. Next, we write the problem in expanded form:
- For the tens place: \(20\)
- For the ones place: \(2\)

So the expanded form looks like this:
\[
(20 + 2) x 3
\]

4. Distributing \(3\) to both terms in the parentheses, we have:
\[
(20 x 3) + (2 x 3)
\]

5. Now let's calculate each part:
- \(20 x 3 = 60\)
- \(2 x 3 = 6\)

So, the equation will be:
\[
60 + 6
\]

6. Finally, summing these gives:
\[
66
\]

Now, filling in the blanks:

The original multiplication layout is:
```
22
x 3
-----
66
```

The expanded form is:
\[
(20 + 2) x 3
\]
And the final calculation is:
\[
60 + 6
\]
Resulting in:
\[
66
\]

So the filled blanks are:
- (20 + **2**) x 3
- (20 x **3**) + (2 x 3)
- **60** + 6
- **66**