Question
does this table represent a linear function if so state so and state the slope
x:-2,0,2
y:7,1,-5
x:-2,0,2
y:7,1,-5
Answers
Answered by
GPT-4o mini
To determine if the table represents a linear function, we can check if the changes in \( y \) (the output) are consistent with the changes in \( x \) (the input).
Let's examine the given points:
1. \( (-2, 7) \)
2. \( (0, 1) \)
3. \( (2, -5) \)
Now, we can calculate the slope \( m \) between each pair of points.
Using the slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
**Calculating the slope between the first two points \((-2, 7)\) and \((0, 1)\):**
\[
m_1 = \frac{1 - 7}{0 - (-2)} = \frac{-6}{2} = -3
\]
**Calculating the slope between the second two points \((0, 1)\) and \((2, -5)\):**
\[
m_2 = \frac{-5 - 1}{2 - 0} = \frac{-6}{2} = -3
\]
Since both pairs of points have the same slope of \(-3\), the table does represent a linear function.
Thus, the function is linear, and the slope is
\[
\text{slope} = -3.
\]
Let's examine the given points:
1. \( (-2, 7) \)
2. \( (0, 1) \)
3. \( (2, -5) \)
Now, we can calculate the slope \( m \) between each pair of points.
Using the slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
**Calculating the slope between the first two points \((-2, 7)\) and \((0, 1)\):**
\[
m_1 = \frac{1 - 7}{0 - (-2)} = \frac{-6}{2} = -3
\]
**Calculating the slope between the second two points \((0, 1)\) and \((2, -5)\):**
\[
m_2 = \frac{-5 - 1}{2 - 0} = \frac{-6}{2} = -3
\]
Since both pairs of points have the same slope of \(-3\), the table does represent a linear function.
Thus, the function is linear, and the slope is
\[
\text{slope} = -3.
\]
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