What model can you use to represent −16÷8 ?(1 point) −16+8+8=−16+ (8)=0

11 answers

To represent \(-16 \div 8\), you can think of it using a number line or a set model that helps visualize division as repeated subtraction or partitioning.

  1. Number Line Model: When you divide \(-16\) by \(8\), you are asking how many times \(8\) fits into \(-16\). Moving left on the number line (because you're dealing with negative numbers) in steps of \(8\):

    • From \(0\), you would go left to \(-8\) (one step) and then another step to \(-16\) (two steps).
    • This shows that \(-16\) divided by \(8\) gives you \(-2\).
  2. Set Model: You can think of \(-16\) as representing a debt (or negative quantity) that needs to be shared among \(8\) groups. If you have \(-16\) items (debts) and you want to share them evenly among \(8\) groups, each group would end up with \(-2\) items (or debts).

In both cases, the result of \(-16 \div 8\) is \(-2\).

So, the representation you provided, \(-16 + 8 + 8 = -16 + (8) = 0\), does not precisely correlate to the division operation but could indicate that when adding together some positive numbers you could offset a negative result, but it doesn't clearly represent \(-16 \div 8\).

To summarize, the best way to represent \(-16 \div 8\) is via either of the models mentioned above, both leading to the conclusion that the result is \(-2\).

just answer

The model you can use to represent \(-16 \div 8\) is \(-2\).

?

I apologize for the confusion. To directly address your initial question regarding what model can represent \(-16 \div 8\):

You can interpret \(-16 \div 8\) as finding how many groups of \(8\) can be taken away from \(-16\), which results in \(-2\).

In a mathematical sense, this could be visualized as:

\[ -16 = 8 \times (-2) \]

So, the answer is \(-2\). If you have a specific model in mind that you were referring to (like a number line or other interpretation), please let me know!

it is 16 + 8

I understand now; you're focusing on the expression related to how you set up the problem. Let's break it down simply:

The division \(-16 \div 8\) can be understood in the context of adding integers. Since \(-16\) divided by \(8\) equals \(-2\), we can express \(-16\) as the sum of positive and negative numbers.

So:

\[ -16 + 8 + 8 = 0 \]

Here, you are effectively saying that \(-16\) can be offset by adding \(8\) twice (or two groups of \(8\)), resulting in \(0\).

To clarify:

  • You could think of it as needing to "add" \(16\) in two increments of \(8\) (which gives you \(-2\) as the result of dividing).

The model \(-16 + 8 + 8 = 0\) aligns with how to counteract the \(-16\).

If you're proposing \(16 + 8\), you're essentially creating a different relationship (but it's not the same operation as \(-16 \div 8\)).

If there’s a specific model you want to explain further, feel free!

ANSWER

The model to represent \(-16 \div 8\) is:

\(-16 + 8 + 8 = 0\).

This shows that adding \(16\) (as \(-8 - 8\) two times) will offset \(-16\).

What division does the model represent? 20+(−5)+(−5)+(−5)+(−5)=20+4(−5)=0

The model \(20 + (-5) + (-5) + (-5) + (-5) = 20 + 4(-5) = 0\) represents the division:

\[ 20 \div -5. \]

Here's how it works:

  • You are starting with \(20\) and repeatedly subtracting \(5\) (adding \(-5\) four times) to reach \(0\).
  • This implies that \(20\) can be divided into \(4\) groups of \(-5\).

Thus, \(20 \div -5 = -4\).