Lets explore why carrying works. First, write each number in expanded form.

_ 10
900 + _ + 6
+200 + 80 + 7
------------------------
_ + 200 + _ + 3
Adding all of these numbers together we get 1,243.

1 answer

To express each number in expanded form for the addition given, we can break them down as follows:

  1. The first number, which is unspecified, can be represented as \( _ = a \) (we will determine it later).

  2. The second number, in expanded form, is: \[ 900 + b + 6 \] where \( b \) is also unspecified.

  3. The third number is: \[ 200 + 80 + 7 \]

  4. The fourth number, which is unspecified, is: \[ _ + 200 + c + 3 \] where \( c \) is also unspecified.

Now, let's organize what we have:

  1. First number: \( a \) (unknown)
  2. Second number: \( 900 + b + 6 \) (which equals \( 906 + b \))
  3. Third number: \( 200 + 80 + 7 \) equals \( 287 \)
  4. Fourth number: \( d + 200 + c + 3 \) (where \( d \) is also unknown)

Now we are working with the equation: \[ a + (900 + b + 6) + (200 + 80 + 7) + (d + 200 + c + 3) = 1243 \] \[ a + (906 + b) + 287 + (d + 200 + c + 3) = 1243 \] \[ a + (906 + b + d + c + 490) = 1243 \]

Now simplifying this we get: \[ a + b + c + d + 1396 = 1243 \]

Now we need to isolate \( a + b + c + d \): \[ a + b + c + d = 1243 - 1396 \] \[ a + b + c + d = -153 \]

This means that:

  • The first number \( a \) can be a negative number,
  • The second number can be defined as \( 906 + b \) (where we might have guessed values for \( b \) later to make sense of it),
  • The other numbers follow the same pattern.

We can conclude that:

Now knowing that the total equals 1243 and how each component contributes, let's say \( a, b, c, \text{ and } d\) all contribute negatively in a way that sums to -153 when you adjust the others positively.

From here:

  • If you assign \( a = -100 \), \( b = -50 \) etc., until they add up with their positive weights to satisfy the equation, you can explore various combinations of carrying effects in individual terms accounting to higher place values, which can make:

an example calculation could look:

  • \( a = 1 \) (1 as first number),
  • \( b = 5 \) (since \( 906 + 5 = 911\)),
  • \( c = 1\) and \( d = 0\), or so forth to require exact adjustment to reach a balanced total of 1243.

Please let me know if you want me to clarify or expand upon specific numbers!