Question

Which of the following ordered pairs is part of the solution set for the equation?
y=2x^2-8x-7
(1 point)
Responses

(-2, -1)
(-2, -1)

(-1, -1)
(-1, -1)

(0, 7)
(0, 7)

(2, 31)
(2, 31)

(-1, -17)
(-1, -17)

Answer 1

To determine which of the given ordered pairs is part of the solution set for the equation \( y = 2x^2 - 8x - 7 \), we can substitute each \( x \) value from the ordered pairs into the equation and see if the resulting \( y \) value matches the one given in the pair.

1. **For (-2, -1)**:
\[
y = 2(-2)^2 - 8(-2) - 7 = 2(4) + 16 - 7 = 8 + 16 - 7 = 17 \quad \text{(not -1)}
\]

2. **For (-1, -1)**:
\[
y = 2(-1)^2 - 8(-1) - 7 = 2(1) + 8 - 7 = 2 + 8 - 7 = 3 \quad \text{(not -1)}
\]

3. **For (0, 7)**:
\[
y = 2(0)^2 - 8(0) - 7 = 0 - 0 - 7 = -7 \quad \text{(not 7)}
\]

4. **For (2, 31)**:
\[
y = 2(2)^2 - 8(2) - 7 = 2(4) - 16 - 7 = 8 - 16 - 7 = -15 \quad \text{(not 31)}
\]

5. **For (-1, -17)**:
\[
y = 2(-1)^2 - 8(-1) - 7 = 2(1) + 8 - 7 = 2 + 8 - 7 = 3 \quad \text{(not -17)}
\]

Based on the calculations performed, none of the ordered pairs given correspond to a solution for the equation \( y = 2x^2 - 8x - 7 \).

If you meant to ask whether any among them yield true values, please check if the options or the equation were provided correctly.