Question
What is the midpoint of this line segment? (1 point) Responses (2,2) (2,2) (-2,-2) (-2,-2) (1/2, -1/2) (1/2, -1/2) (-5/2, -3/2)
Answers
Answer
E is, (-6,1) and F is, (2,-5)
Answer
E is, (-6,1) and F is, (-5,2)
Answer
E is, (1,-6) and F is, (-5,2)
Answered by
GPT-4o mini
To find the midpoint of a line segment, we use the midpoint formula, which is given by:
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
You need to specify the endpoints of the line segment (let's call them \( (x_1, y_1) \) and \( (x_2, y_2) \)) in order to calculate the midpoint. Without that information, I cannot calculate the midpoint for you.
If you provide the coordinates of the endpoints, I can then compute the midpoint.
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
You need to specify the endpoints of the line segment (let's call them \( (x_1, y_1) \) and \( (x_2, y_2) \)) in order to calculate the midpoint. Without that information, I cannot calculate the midpoint for you.
If you provide the coordinates of the endpoints, I can then compute the midpoint.
Answered by
GPT-4o mini
To find the midpoint of the line segment joining the points \( E(-6, 1) \) and \( F(2, -5) \), we will use the midpoint formula:
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
In this case:
- \( E(x_1, y_1) = (-6, 1) \)
- \( F(x_2, y_2) = (2, -5) \)
Now we can plug the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{-6 + 2}{2}, \frac{1 + (-5)}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{-6 + 2}{2} = \frac{-4}{2} = -2
\]
Calculating the y-coordinate:
\[
\frac{1 - 5}{2} = \frac{-4}{2} = -2
\]
So, the midpoint \( M \) is:
\[
M = (-2, -2)
\]
Thus, the midpoint of the segment EF is \( (-2, -2) \).
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
In this case:
- \( E(x_1, y_1) = (-6, 1) \)
- \( F(x_2, y_2) = (2, -5) \)
Now we can plug the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{-6 + 2}{2}, \frac{1 + (-5)}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{-6 + 2}{2} = \frac{-4}{2} = -2
\]
Calculating the y-coordinate:
\[
\frac{1 - 5}{2} = \frac{-4}{2} = -2
\]
So, the midpoint \( M \) is:
\[
M = (-2, -2)
\]
Thus, the midpoint of the segment EF is \( (-2, -2) \).
Answered by
GPT-4o mini
To find the midpoint of the line segment connecting the points \( E(-6, 1) \) and \( F(-5, 2) \), we will use the midpoint formula:
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Where:
- \( E(x_1, y_1) = (-6, 1) \)
- \( F(x_2, y_2) = (-5, 2) \)
Now we can substitute the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{-6 + (-5)}{2}, \frac{1 + 2}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{-6 - 5}{2} = \frac{-11}{2} = -\frac{11}{2}
\]
Calculating the y-coordinate:
\[
\frac{1 + 2}{2} = \frac{3}{2}
\]
So, the midpoint \( M \) is:
\[
M = \left( -\frac{11}{2}, \frac{3}{2} \right)
\]
Thus, the midpoint of the segment \( EF \) is \( \left( -\frac{11}{2}, \frac{3}{2} \right) \).
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Where:
- \( E(x_1, y_1) = (-6, 1) \)
- \( F(x_2, y_2) = (-5, 2) \)
Now we can substitute the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{-6 + (-5)}{2}, \frac{1 + 2}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{-6 - 5}{2} = \frac{-11}{2} = -\frac{11}{2}
\]
Calculating the y-coordinate:
\[
\frac{1 + 2}{2} = \frac{3}{2}
\]
So, the midpoint \( M \) is:
\[
M = \left( -\frac{11}{2}, \frac{3}{2} \right)
\]
Thus, the midpoint of the segment \( EF \) is \( \left( -\frac{11}{2}, \frac{3}{2} \right) \).
Answered by
GPT-4o mini
To find the midpoint of the line segment connecting the points \( E(1, -6) \) and \( F(-5, 2) \), we will use the midpoint formula:
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Where:
- \( E(x_1, y_1) = (1, -6) \)
- \( F(x_2, y_2) = (-5, 2) \)
Now we can substitute the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{1 + (-5)}{2}, \frac{-6 + 2}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{1 - 5}{2} = \frac{-4}{2} = -2
\]
Calculating the y-coordinate:
\[
\frac{-6 + 2}{2} = \frac{-4}{2} = -2
\]
So, the midpoint \( M \) is:
\[
M = (-2, -2)
\]
Thus, the midpoint of the segment \( EF \) is \( (-2, -2) \).
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
Where:
- \( E(x_1, y_1) = (1, -6) \)
- \( F(x_2, y_2) = (-5, 2) \)
Now we can substitute the coordinates into the formula:
\[
\text{Midpoint} = \left( \frac{1 + (-5)}{2}, \frac{-6 + 2}{2} \right)
\]
Calculating the x-coordinate:
\[
\frac{1 - 5}{2} = \frac{-4}{2} = -2
\]
Calculating the y-coordinate:
\[
\frac{-6 + 2}{2} = \frac{-4}{2} = -2
\]
So, the midpoint \( M \) is:
\[
M = (-2, -2)
\]
Thus, the midpoint of the segment \( EF \) is \( (-2, -2) \).