Question

Mr. Hibbard found a magic penny which doubles in value every day. The expression .01⋅2^x
where x is the number of days since Mr. Hibbard found the penny.



Mr. Hibbard realized after just 2 weeks the penny had become $163.84! How did he reach this solution

(1 point)
Responses

Mr. Hibbard substituted x = 14 into the expression .01⋅2^14=163.48
Mr. Hibbard substituted x = 14 into the expression point 0 1 times 2 to the 14th power is equal to 163 point 4 8

Mr. Hibbard substituted x = 2 into the expression .01⋅2⋅2=163.48
Mr. Hibbard substituted x = 2 into the expression point 0 1 times 2 times 2 is equal to 163 point 4 8

Mr. Hibbard substituted x = 14 into the expression .01⋅2⋅14=163.48
Mr. Hibbard substituted x = 14 into the expression point 0 1 times 2 times 14 is equal to 163 point 4 8

Mr. Hibbard substituted x = 2 into the expression .01⋅2^2=163.48

Answer 1

Mr. Hibbard correctly substituted \( x = 14 \) into the expression \( 0.01 \cdot 2^{14} \) to find the value of the penny after 14 days. The calculation would be:

\[
0.01 \cdot 2^{14} = 0.01 \cdot 16384 = 163.84
\]

So the correct response is:

**Mr. Hibbard substituted x = 14 into the expression .01⋅2^14=163.84.**