To simplify the expression \( 125^3 \div 75^3 \) using the Quotient Rule of Integer Exponents, we can first rewrite the bases in terms of their prime factors:
- Rewrite \( 125 \) and \( 75 \):
- \( 125 = 5^3 \)
- \( 75 = 3 \times 5^2 \)
Thus, we can express the entire expression as: \[ \frac{125^3}{75^3} = \frac{(5^3)^3}{(3 \times 5^2)^3} \]
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Apply the power of a power rule: \[ = \frac{5^{3 \cdot 3}}{(3^3) \cdot (5^2)^3} = \frac{5^9}{27 \cdot 5^6} \]
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Now we can use the Quotient Rule of Integer Exponents, which states \( \frac{a^m}{a^n} = a^{m-n} \): \[ = \frac{5^9}{27} \cdot \frac{1}{5^6} = \frac{5^{9-6}}{27} = \frac{5^3}{27} \]
Thus, the expression simplifies to \( \frac{5^3}{27} \).
None of the provided options appear to match this simplified form correctly. However, if the question intended a different interpretation, please take note. In a strict sense of simplification and re-evaluation of the options, the expression remains \( \frac{5^3}{27} \).