What are the roots of g(x)=4x2+256? Provide the exact answers. Enter the smaller number first.(1 point)

1 answer

To find the roots of the quadratic equation \( g(x) = 4x^2 + 256 \), we need to set \( g(x) = 0 \):

\[ 4x^2 + 256 = 0 \]

Subtracting 256 from both sides, we have:

\[ 4x^2 = -256 \]

Next, divide by 4:

\[ x^2 = -64 \]

To solve for \( x \), we take the square root of both sides:

\[ x = \pm \sqrt{-64} \]

Since the square root of a negative number involves the imaginary unit \( i \):

\[ x = \pm 8i \]

Thus, the roots of the equation \( g(x) = 4x^2 + 256 \) are:

\[ -8i \quad \text{and} \quad 8i \]

When writing the roots in order from smaller to larger, we get:

\[ -8i, 8i \]

So, the exact answers are:

\[ -8i, 8i \]