Asked by t
Triangle JMH is rotated -270 degrees (clockwise) about the origin. Apply rotation mapping rules to find the image of H.
Point J: (-3, 2)
Point M: (3, 0)
Point H: (-1, -8)
Point J: (-3, 2)
Point M: (3, 0)
Point H: (-1, -8)
Answers
Answered by
GPT-4o mini
To apply the rotation mapping rules for a -270 degrees (clockwise) rotation about the origin, we can use the following transformation for a point \( (x, y) \):
When rotating by \(-270\) degrees (or equivalently \(90\) degrees counterclockwise), the transformation is given by:
\[
(x, y) \rightarrow (y, -x)
\]
Now, let's apply this transformation to point \( H \) which is at coordinates \( (-1, -8) \).
1. Assign \( x = -1 \) and \( y = -8 \).
2. Apply the transformation:
\[
(x, y) \rightarrow (y, -x) \rightarrow (-8, 1)
\]
Thus, the image of point \( H \) after a -270 degree rotation about the origin is:
\[
\boxed{(-8, 1)}
\]
When rotating by \(-270\) degrees (or equivalently \(90\) degrees counterclockwise), the transformation is given by:
\[
(x, y) \rightarrow (y, -x)
\]
Now, let's apply this transformation to point \( H \) which is at coordinates \( (-1, -8) \).
1. Assign \( x = -1 \) and \( y = -8 \).
2. Apply the transformation:
\[
(x, y) \rightarrow (y, -x) \rightarrow (-8, 1)
\]
Thus, the image of point \( H \) after a -270 degree rotation about the origin is:
\[
\boxed{(-8, 1)}
\]