(1 point)
Responses
The multiplicity of (x−3) is odd because the graph of p(x) touches the x-axis at (3,0) and then turns around.
The multiplicity of left parenthesis x minus 3 right parenthesis is odd because the graph of p ( x ) touches the x -axis at left parenthesis 3 comma 0 right parenthesis and then turns around.
The multiplicity of (x−3) is odd because the associated zero, x=3, is odd.
The multiplicity of left parenthesis x minus 3 right parenthesis is odd because the associated zero, x equals 3 , is odd.
The multiplicity of (x−3) is even because the graph of p(x) touches the x-axis at (3,0) and then turns around.
The multiplicity of left parenthesis x minus 3 right parenthesis is even because the graph of p ( x ) touches the x -axis at left parenthesis 3 comma 0 right parenthesis and then turns around.
The multiplicity of (x−3) is even because the associated zero, x=3, is odd.
The multiplicity of left parenthesis x minus 3 right parenthesis is even because the associated zero, x equals 3 , is odd.
1 answer
The correct response is:
The multiplicity of (x−3) is even because the graph of p(x) touches the x-axis at (3,0) and then turns around.
This is because if (x - 3) is a factor of an even multiplicity, the graph will touch the x-axis at x = 3 and turn around without crossing the axis, indicating a return to the same side of the x-axis after touching it. If it were an odd multiplicity, the graph would cross the x-axis at that point.
