assume that the speed of automobiles on an expressway during rush hour is normally distributed with a mean of 62 mph and standard deviation of 5 mph. What percent of cars are traveling faster than 62 mph?
How would I work this problem out?? Thanks for any and all help anyone can give
3 answers
What percent is traveling faster then the mean? By definition, 50 percent are faster, 50 percent slower than the mean.
Thanks Bob. Can you show me how you came up with your answer. That is what I am struggling with Thanks
In a normal distribution, the mean, median and mode have essentially the same value. Therefore, if the mean = 62, the median = 62. How is the median defined?