To balance the given equation \( \text{CH} + _____\text{Cl} \rightarrow \text{CCl} + _____\text{HCl} \), we need to ensure that the number of each type of atom on the reactants side matches the number on the products side.
Let's denote the missing coefficients:
- Let \( a \) be the coefficient for Cl.
- Let \( b \) be the coefficient for HCl.
The unbalanced equation is: \[ \text{CH} + a \text{Cl} \rightarrow \text{CCl} + b \text{HCl} \]
Balancing carbon:
- There is 1 C in CH and 1 C in CCl, so carbon is balanced.
Balancing hydrogen:
- There is 1 H in CH and \( b \) H in HCl. This gives us: \[ 1 = b \]
Balancing chlorine:
- On the left, we have \( a \) Cl, and on the right, we have \( 1 \) Cl in CCl and \( b \) Cl in HCl. Therefore: \[ a = 1 + b \]
Substituting \( b = 1 \) from the hydrogen balance into the chlorine balance gives us: \[ a = 1 + 1 \] \[ a = 2 \]
Now we have:
- \( a = 2 \) (for Cl)
- \( b = 1 \) (for HCl)
Putting it together, we can write the balanced equation: \[ \text{1 CH} + \text{2 Cl} \rightarrow \text{1 CCl} + \text{1 HCl} \]
The coefficients that balance the equation are \( 1, 2 \).
Thus, the correct answer is 1, 2.
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