Question

Were these values from least to greatest

π, √6, 7/2, 3.25

Answer 1

To compare the values \( \pi, \sqrt{6}, \frac{7}{2}, \) and \( 3.25 \), we first need to approximate each of them:

1. \( \pi \approx 3.14 \)
2. \( \sqrt{6} \approx 2.45 \) (because \( 2.45^2 \approx 6 \))
3. \( \frac{7}{2} = 3.5 \)
4. \( 3.25 = 3.25 \)

Now, we can compare them:

- \( \sqrt{6} \approx 2.45 \)
- \( \pi \approx 3.14 \)
- \( 3.25 = 3.25 \)
- \( \frac{7}{2} = 3.5 \)

Arranging these values from least to greatest, we have:

1. \( \sqrt{6} \)
2. \( \pi \)
3. \( 3.25 \)
4. \( \frac{7}{2} \)

Therefore, the values in order from least to greatest are:

\[
\sqrt{6}, \pi, 3.25, \frac{7}{2}
\]