Rewrite the following expressions: 2712⋅2714

To rewrite the expression \( 2712 \cdot 2714 \), we can simplify it as follows:

1. Recognize that \( 2712 \) and \( 2714 \) can be expressed in terms of \( 2713 \):
\[
2712 = 2713 - 1
\]
\[
2714 = 2713 + 1
\]

2. Thus, we have:
\[
2712 \cdot 2714 = (2713 - 1)(2713 + 1)
\]

3. This expression can be simplified using the difference of squares:
\[
(a - b)(a + b) = a^2 - b^2
\]
where \( a = 2713 \) and \( b = 1 \):
\[
2712 \cdot 2714 = 2713^2 - 1^2 = 2713^2 - 1
\]

Now, let's present this result in a simplified form:

- Since \( 2713 \) is \( 27^{1.5} \) or \( 27^{3/2} \), we can rewrite the final expression in terms of powers of \( 27 \):
\[
2712 \cdot 2714 = 27^{3/2}^2 - 1 = 27^3 - 1
\]

Therefore, the final expression can be stated as:

\[
27^{3} - 1
\]

This result can also be expressed as:

\[
27^{3} - 1
\]

Let me know if you need a particular format for the answer or anything else!