To determine which of the ordered pairs is a solution to the equation \( 8 - 2y = 4x^2 \), we will substitute each pair into the equation.
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Option #1: \( (0, 8) \)
- Substitute \( x = 0 \) and \( y = 8 \): \[ 8 - 2(8) = 4(0)^2 \] \[ 8 - 16 = 0 \] \[ -8 \neq 0 \] So, \( (0, 8) \) is not a solution.
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Option #2: \( (-1, 2) \)
- Substitute \( x = -1 \) and \( y = 2 \): \[ 8 - 2(2) = 4(-1)^2 \] \[ 8 - 4 = 4 \] \[ 4 = 4 \] So, \( (-1, 2) \) is a solution.
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Option #3: \( (4, 0) \)
- Substitute \( x = 4 \) and \( y = 0 \): \[ 8 - 2(0) = 4(4)^2 \] \[ 8 = 4(16) \] \[ 8 = 64 \] So, \( (4, 0) \) is not a solution.
The only ordered pair that is a solution to the equation \( 8 - 2y = 4x^2 \) is Option #2: \( (-1, 2) \).