Question

What is the quotient of \frac{14x^2-21}{7}?

Answer 1

To find the quotient of \(\frac{14x^2 - 21}{7}\), we can divide each term in the numerator by 7.

Starting with the expression:

\[
\frac{14x^2 - 21}{7}
\]

We can split this into two separate fractions:

\[
\frac{14x^2}{7} - \frac{21}{7}
\]

Now, we can simplify each fraction:

1. \(\frac{14x^2}{7} = 2x^2\)
2. \(\frac{21}{7} = 3\)

Putting these simplifications together, we get:

\[
2x^2 - 3
\]

Thus, the quotient of \(\frac{14x^2 - 21}{7}\) is:

\[
\boxed{2x^2 - 3}
\]