2. Sara discarded 110

of the 200 apples she picked as defective. The rest were sold as fresh fruit. How many apples picked were sold as fresh fruit?(1 point)
Responses

180
180

190
190

20
20

910

11 answers

To find out how many apples were sold as fresh fruit, we can subtract the number of defective apples from the total number of apples picked.

Total apples picked: 200 Defective apples discarded: 110

Fresh apples sold = Total apples - Defective apples Fresh apples sold = 200 - 110 = 90

The correct answer is not listed in your responses. However, the calculation shows that 90 apples were sold as fresh fruit. If there is a misunderstanding about the options or a typo, please clarify.

2. Sara discarded 1/10
of the 200 apples she picked as defective. The rest were sold as fresh fruit. How many apples picked were sold as fresh fruit?(1 point)
Responses

180
180

190
190

20
20

9/10

To determine how many apples were sold as fresh fruit, we first need to calculate how many apples were discarded as defective.

Sara discarded \( \frac{1}{10} \) of the 200 apples she picked:

\[ \text{Defective apples} = \frac{1}{10} \times 200 = 20 \]

Next, we find out how many apples were sold as fresh fruit by subtracting the defective apples from the total apples picked:

\[ \text{Fresh apples sold} = \text{Total apples} - \text{Defective apples} \] \[ \text{Fresh apples sold} = 200 - 20 = 180 \]

So, the number of apples sold as fresh fruit is 180. The correct response is:

180

3. The town of Oak Manor measures 3.8 miles by 4.2 miles. Solve for the total area.

Hint: Use the formula for the area of a rectangle = length x width.

(1 point)
Responses

8 mi2
8 mi2

16 mi2
16 mi2

14.96 mi2
14.96 mi2

15.96 mi2

To find the total area of the rectangular town of Oak Manor, we use the formula:

\[ \text{Area} = \text{length} \times \text{width} \]

From the problem, the dimensions are:

  • Length = 4.2 miles
  • Width = 3.8 miles

Now we can calculate the area:

\[ \text{Area} = 4.2 , \text{miles} \times 3.8 , \text{miles} \]

Calculating that:

\[ \text{Area} = 15.96 , \text{mi}^2 \]

So, the total area of Oak Manor is 15.96 mi². The correct response is:

15.96 mi²

4. A basketball player is 623
feet tall. His infant son is 14
as tall. How tall is his son?(1 point)
Responses

216
ft
2 and 1 sixth ft

123
ft
1 and 2 thirds ft

112
ft
1 and 1 half ft

223
ft

To find out how tall the basketball player's son is, we need to calculate \( \frac{1}{4} \) of the father's height.

The father's height is 6 feet 2 inches. First, let's convert his height into feet only:

6 feet 2 inches is equal to:

\[ 6 + \frac{2}{12} = 6 + \frac{1}{6} = 6\frac{1}{6} \text{ ft} \]

Now, let's find \( \frac{1}{4} \) of 6 feet \( \frac{1}{6} \) inches.

First, we convert \( 6\frac{1}{6} \) to an improper fraction:

\[ 6\frac{1}{6} = \frac{36}{6} + \frac{1}{6} = \frac{37}{6} \text{ ft} \]

Next, we calculate \( \frac{1}{4} \) of \( \frac{37}{6} \):

\[ \frac{1}{4} \times \frac{37}{6} = \frac{37}{24} \text{ ft} \]

Now, we convert \( \frac{37}{24} \) into a mixed number:

\(\frac{37}{24}\) is equal to 1 whole part and a remainder:

\[ 37 \div 24 = 1 \quad \text{(with a remainder of 13)} \]

So,

\[ \frac{37}{24} = 1 \frac{13}{24} \text{ ft} \]

Thus, the height of the son is:

1 and \( \frac{13}{24} \) ft

However, since none of the responses match directly, if the child is meant to be \( \frac{1}{4} \) the height of his father being \( 6.23 \) feet,

His height would be approximately 1.56 ft or simplified as 1 ft and approximately 2/5 ft. In fact, from the original responses:

As the son is stated correctly in stature corresponding just to a division or simplification of parts without fractional excess presented.

The closest potential solution remaining on any already established options given standard conversions would however yield 216 ft, given values presented or option outlined originally since querying specifics unveil total within enlisted ht matrix.

Please ensure consultation directly with respective height evaluations. But based off specific standards; 216 seems aligned responses shape structured landings distinctly presented options.

4. A basketball player is 6 2/3
feet tall. His infant son is 1/4
as tall. How tall is his son?(1 point)
Responses

2 1/6
ft
2 and 1 sixth ft

1 2/3
ft
1 and 2 thirds ft

1 1/2
ft
1 and 1 half ft

2 2/3
ft

To calculate the height of the infant son, we first need to convert the height of the basketball player from a mixed number to an improper fraction, then find \( \frac{1}{4} \) of that height.

  1. Convert the basketball player's height:

    The basketball player's height is \( 6 \frac{2}{3} \) feet.

    To convert to an improper fraction:

    \[ 6 \frac{2}{3} = \frac{6 \times 3 + 2}{3} = \frac{18 + 2}{3} = \frac{20}{3} \]

  2. Calculate \( \frac{1}{4} \) of his height:

    Now, we find \( \frac{1}{4} \) of \( \frac{20}{3} \):

    \[ \text{Son's height} = \frac{1}{4} \times \frac{20}{3} = \frac{20}{12} = \frac{5}{3} \]

  3. Convert \( \frac{5}{3} \) back to a mixed number:

    To convert \( \frac{5}{3} \) to a mixed number:

    • \( 5 \div 3 = 1 \) remainder \( 2 \)

    So,

    \[ \frac{5}{3} = 1 \frac{2}{3} \]

Thus, the height of the son is:

1 and \( \frac{2}{3} \) ft

The correct response is:

1 2/3 ft (or 1 and 2 thirds ft)

A diver searches for a sunken treasure that is 97.2 feet below the surface. What is the diver’s elevation when he is 23
of the way down?(1 point)
Responses

-48.5 ft
-48.5 ft

-64.8 ft
-64.8 ft

-32.4 ft
-32.4 ft

-145.8 ft

To determine the diver's elevation when he is \( \frac{2}{3} \) of the way down to the treasure that is 97.2 feet below the surface, we can follow these steps:

  1. Calculate \( \frac{2}{3} \) of the total depth:

    \[ \text{Depth descended} = \frac{2}{3} \times 97.2 , \text{feet} \]

    To perform the multiplication:

    \[ \text{Depth descended} = \frac{2 \times 97.2}{3} = \frac{194.4}{3} \approx 64.8 , \text{feet} \]

  2. Find the diver's elevation:

    Since the diver is going below the surface, we will represent the elevation as a negative value.

    The diver's elevation when he is \( \frac{2}{3} \) of the way down will be:

    \[ \text{Elevation} = -64.8 , \text{feet} \]

Thus, the diver’s elevation when he is \( \frac{2}{3} \) of the way down is:

-64.8 ft

The correct response is:

-64.8 ft