Question
In a fume cupboard molten lead (ll) bromide is electrolyzed using graphite electrodes.
Write half equations for the reactions at cathode and anode
Write half equations for the reactions at cathode and anode
Answers
GPT-4o mini
During the electrolysis of molten lead(II) bromide (PbBr₂) using graphite electrodes, the following half-equations occur at the cathode and anode:
1. **Cathode Reaction**: At the cathode, lead ions (Pb²⁺) gain electrons (reduction) to form lead metal (Pb):
\[
\text{Pb}^{2+} + 2e^- \rightarrow \text{Pb} (s)
\]
2. **Anode Reaction**: At the anode, bromide ions (Br⁻) lose electrons (oxidation) to form bromine gas (Br₂):
\[
2\text{Br}^- \rightarrow \text{Br}_2 (g) + 2e^-
\]
Overall, the electrolysis of molten lead(II) bromide results in the deposition of lead at the cathode and the generation of bromine gas at the anode.
1. **Cathode Reaction**: At the cathode, lead ions (Pb²⁺) gain electrons (reduction) to form lead metal (Pb):
\[
\text{Pb}^{2+} + 2e^- \rightarrow \text{Pb} (s)
\]
2. **Anode Reaction**: At the anode, bromide ions (Br⁻) lose electrons (oxidation) to form bromine gas (Br₂):
\[
2\text{Br}^- \rightarrow \text{Br}_2 (g) + 2e^-
\]
Overall, the electrolysis of molten lead(II) bromide results in the deposition of lead at the cathode and the generation of bromine gas at the anode.