To multiply the polynomials \( (4x^2 + 7x - 3) \) and \( (2x^2 + 7x - 5) \), we can use the distributive property, also known as the FOIL method for binomials, but here we will distribute each term of the first polynomial across each term of the second polynomial.
Let's carry out the multiplication step by step.
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Multiply \( 4x^2 \) by each term in the second polynomial: \[ 4x^2 \cdot 2x^2 = 8x^4 \] \[ 4x^2 \cdot 7x = 28x^3 \] \[ 4x^2 \cdot -5 = -20x^2 \]
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Multiply \( 7x \) by each term in the second polynomial: \[ 7x \cdot 2x^2 = 14x^3 \] \[ 7x \cdot 7x = 49x^2 \] \[ 7x \cdot -5 = -35x \]
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Multiply \( -3 \) by each term in the second polynomial: \[ -3 \cdot 2x^2 = -6x^2 \] \[ -3 \cdot 7x = -21x \] \[ -3 \cdot -5 = 15 \]
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Now, combine all these results together: \[ 8x^4 + 28x^3 - 20x^2 + 14x^3 + 49x^2 - 35x - 6x^2 - 21x + 15 \]
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Combine like terms:
- For \( x^4 \): \( 8x^4 \)
- For \( x^3 \): \( 28x^3 + 14x^3 = 42x^3 \)
- For \( x^2 \): \( -20x^2 + 49x^2 - 6x^2 = 23x^2 \)
- For \( x \): \( -35x - 21x = -56x \)
- Constant: \( 15 \)
Thus, the final result of the multiplication is: \[ \boxed{8x^4 + 42x^3 + 23x^2 - 56x + 15} \]