Shilongo has a sum of money. He gave half of this money to his wife and than N$ 800, which is a third of the remainder, to his son Andrew. How much did Shilongo's wife get from her husband?

Answer 1

Let's denote the total sum of money that Shilongo has as \( x \).

1. Shilongo gave half of this amount to his wife: \[ \text{Amount given to wife} = \frac{x}{2} \]

2. After giving half to his wife, the remaining amount is: \[ \text{Remainder} = x - \frac{x}{2} = \frac{x}{2} \]

3. Shilongo then gave N$ 800 to his son Andrew, which is one third of the remainder: \[ \frac{1}{3} \cdot \left(\frac{x}{2}\right) = 800 \]

   To find \( x \), we set up the equation: \[ \frac{x}{6} = 800 \]

4. To solve for \( x \), we multiply both sides by 6: \[ x = 800 \times 6 = 4800 \]

5. Now we can find how much Shilongo's wife received: \[ \text{Amount given to wife} = \frac{4800}{2} = 2400 \]

Therefore, Shilongo's wife received N$ 2400 from her husband.