Add the polynomial expressions 2r2−3r+42r2−3r+4 and −2r2+3r+6−2r2+3r+6 .(1 point)

To add the polynomial expressions \( 2r^2 - 3r + 4 \) and \( -2r^2 + 3r + 6 \), we'll combine like terms.

Let's write down the two expressions:

1. \( 2r^2 - 3r + 4 \)
2. \( -2r^2 + 3r + 6 \)

Now we add them together:

\[
(2r^2 - 3r + 4) + (-2r^2 + 3r + 6)
\]

Combine the like terms:

- For \( r^2 \) terms: \( 2r^2 + (-2r^2) = 0r^2 \)
- For \( r \) terms: \( -3r + 3r = 0r \)
- For constant terms: \( 4 + 6 = 10 \)

Putting it all together, we get:

\[
0r^2 + 0r + 10 = 10
\]

Thus, the sum of the polynomial expressions is \( \boxed{10} \).