Asked by Laverne

A 155g sample of an unknown was heated from 25.0 to 40.00c absorbing 5696J of energy. what is the specific heat?

15 years ago

Answered by DrBob222

q = m*c*delta T

15 years ago

Answered by Rita

155g * 5696J * 15c (convert 15c to Joules)

15 years ago

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