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To convert the linear equation \(3x + 4y = 8\) into slope-intercept form, which is \(y = mx + b\) (where \(m\) is the slope and \(b\) is the y-intercept), we need to solve for \(y\).
Starting with the original equation:
\[
3x + 4y = 8
\]
Subtract \(3x\) from both sides:
\[
4y = -3x + 8
\]
Next, divide every term by \(4\):
\[
y = -\frac{3}{4}x + 2
\]
Now, the equation is in slope-intercept form \(y = mx + b\), where \(m = -\frac{3}{4}\) (the slope) and \(b = 2\) (the y-intercept).
Thus, the slope-intercept form of the equation \(3x + 4y = 8\) is:
\[
y = -\frac{3}{4}x + 2
\]