Question

A recipe calls for 3 1/3 cups of flour. Charlie only has a 1/3-cup measuring cup. How many times will Charlie need to fill the 1/3-cup
measuring cup? Set up the initial problem on the left side of the equation and the solution on the right side of the equation.

Answer 1

To determine how many times Charlie needs to fill the 1/3-cup measuring cup to measure out 3 1/3 cups of flour, we can set up the equation like this:

**Initial Problem:**

\[
3 \frac{1}{3} \div \frac{1}{3}
\]

**Solution:**

First, let's convert the mixed number \(3 \frac{1}{3}\) into an improper fraction:

\[
3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3}
\]

Now we need to divide \(\frac{10}{3}\) by \(\frac{1}{3}\):

\[
\frac{10}{3} \div \frac{1}{3}
\]

Dividing by a fraction is the same as multiplying by its reciprocal, so we have:

\[
\frac{10}{3} \times \frac{3}{1} = \frac{10 \times 3}{3 \times 1} = \frac{30}{3} = 10
\]

Thus, the final equation is:

\[
3 \frac{1}{3} \div \frac{1}{3} = 10
\]

**Conclusion:**

Charlie will need to fill the 1/3-cup measuring cup **10 times**.