To determine which ordered pair is a solution to the equation \( 8 - 2y = 4x^2 \), we will substitute each ordered pair into the equation and see if it holds true.
Option #1: (0, 8)
- Here, \( x = 0 \) and \( y = 8 \).
- Substitute into the equation: \[ 8 - 2(8) = 4(0)^2 \ 8 - 16 = 0 \ -8 \neq 0 \text{ (not a solution)} \]
Option #2: (-1, 2)
- Here, \( x = -1 \) and \( y = 2 \).
- Substitute into the equation: \[ 8 - 2(2) = 4(-1)^2 \ 8 - 4 = 4 \ 4 = 4 \text{ (is a solution)} \]
Option #3: (4, 0)
- Here, \( x = 4 \) and \( y = 0 \).
- Substitute into the equation: \[ 8 - 2(0) = 4(4)^2 \ 8 - 0 = 4(16) \ 8 = 64 \text{ (not a solution)} \]
Based on the calculations, the only ordered pair that is a solution to the equation \( 8 - 2y = 4x^2 \) is:
Option #2: (-1, 2)