To find the product of the polynomials \((9x^2 - 6x + 1)(3x - 1)\), we can use the distributive property (also known as the FOIL method for binomials).
Let's multiply each term in the first polynomial by each term in the second polynomial:
1. **Multiply \(9x^2\) by \(3x\)**:
\[
9x^2 \cdot 3x = 27x^3
\]
2. **Multiply \(9x^2\) by \(-1\)**:
\[
9x^2 \cdot -1 = -9x^2
\]
3. **Multiply \(-6x\) by \(3x\)**:
\[
-6x \cdot 3x = -18x^2
\]
4. **Multiply \(-6x\) by \(-1\)**:
\[
-6x \cdot -1 = 6x
\]
5. **Multiply \(1\) by \(3x\)**:
\[
1 \cdot 3x = 3x
\]
6. **Multiply \(1\) by \(-1\)**:
\[
1 \cdot -1 = -1
\]
Now, combine all these results:
\[
27x^3 + (-9x^2 - 18x^2) + (6x + 3x) - 1
\]
This simplifies to:
\[
27x^3 + (-27x^2) + 9x - 1
\]
So the combined polynomial is:
\[
27x^3 - 27x^2 + 9x - 1
\]
Looking at the response options, the correct answer is:
**27x³ - 27x² + 9x - 1**