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Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 de...Asked by p diddy
solve the following word problem. the air temperature at 9 a.m. is −5.8 − 5.8 degrees celsius. the air temperature at noon is −1.6 − 1.6 degrees celsius. what is the change in the temperature during these three hours? write and solve an equation to show your answer. then explain what your answer means.(4 points)
Answers
Answered by
p diddy
explain in 4 sentences
Answered by
GPT-4o mini
To find the change in temperature from 9 a.m. to noon, we can use the following equation:
\[
\text{Change in temperature} = \text{Temperature at noon} - \text{Temperature at 9 a.m.}
\]
Let's insert the values:
- Temperature at 9 a.m. = \(-5.8\) degrees Celsius
- Temperature at noon = \(-1.6\) degrees Celsius
Now let's write and solve the equation:
\[
\text{Change in temperature} = -1.6 - (-5.8)
\]
This simplifies to:
\[
\text{Change in temperature} = -1.6 + 5.8
\]
Calculating this gives:
\[
\text{Change in temperature} = 4.2
\]
So, the change in temperature during these three hours is \(4.2\) degrees Celsius.
### Explanation of the answer:
This means that the temperature increased by \(4.2\) degrees Celsius from 9 a.m. to noon. The negative temperatures indicate that it was quite cold at both times, but the increase indicates a warming trend over the three-hour period.
\[
\text{Change in temperature} = \text{Temperature at noon} - \text{Temperature at 9 a.m.}
\]
Let's insert the values:
- Temperature at 9 a.m. = \(-5.8\) degrees Celsius
- Temperature at noon = \(-1.6\) degrees Celsius
Now let's write and solve the equation:
\[
\text{Change in temperature} = -1.6 - (-5.8)
\]
This simplifies to:
\[
\text{Change in temperature} = -1.6 + 5.8
\]
Calculating this gives:
\[
\text{Change in temperature} = 4.2
\]
So, the change in temperature during these three hours is \(4.2\) degrees Celsius.
### Explanation of the answer:
This means that the temperature increased by \(4.2\) degrees Celsius from 9 a.m. to noon. The negative temperatures indicate that it was quite cold at both times, but the increase indicates a warming trend over the three-hour period.
Answered by
GPT-4o mini
The change in temperature from 9 a.m. to noon was \(4.2\) degrees Celsius. This calculation shows that the temperature rose from \(-5.8\) degrees Celsius at 9 a.m. to \(-1.6\) degrees Celsius at noon. The increase indicates a warming trend during that time period. It shows that while the temperature remained below freezing, it did become significantly warmer over the course of those three hours.