Question

Apply the zero power role of an integer exponents to solve negative for superscript 0.15

Answer 1

The zero power rule of exponents states that any non-zero number raised to the power of zero equals one. This means that for any integer \( a \) where \( a \neq 0 \):

\[
a^0 = 1
\]

However, when dealing with negative bases, the rule still applies as long as the base is not zero. For example:

\[
(-2)^0 = 1
\]

Now, your question involves a superscript of \( 0.15 \). If you meant to apply the zero power rule to a base of negative integer but with a different exponent, remember that:

\[
a^{-b} = \frac{1}{a^b}
\]

If you want to evaluate \( (-1)^{0.15} \), remember that negative bases raised to fractional exponents can result in complex numbers. However, \( (-1)^0 \) (when exponent is exactly zero) is:

\[
(-1)^0 = 1
\]

If you were specifically looking to apply the rule to say, \( (-c)^0 \) for any negative integer \( c \) or a similar expression:

\[
(-c)^0 = 1
\]

So to summarize:

- For any non-zero base \( a \), \( a^0 = 1 \).
- For negative bases, at \( 0 \) power, it still holds that \( (-a)^0 = 1 \).
- For positive and negative bases with non-integer exponents, be cautious of potential complex results.

If you meant something else or have a specific expression in mind, please clarify!