Question
Use multiplication to find the product that demonstrates the Closure Property of multiplication of polynomials.
(1/2x^2−3)(4y^3+5x^2)
(1 point)
Responses
A. 5/2x^2y^3 + 2x^4 - 8y^3 + 15x^2
B. x^2y^3 + 5/x^4 - 8y^3 - 15x^2
C. 2x^2y^3 + 5/2 x^4 - 12y^3 - 15x^2
D. √x^2y^3 + 4x^4 - 15x^2
(1/2x^2−3)(4y^3+5x^2)
(1 point)
Responses
A. 5/2x^2y^3 + 2x^4 - 8y^3 + 15x^2
B. x^2y^3 + 5/x^4 - 8y^3 - 15x^2
C. 2x^2y^3 + 5/2 x^4 - 12y^3 - 15x^2
D. √x^2y^3 + 4x^4 - 15x^2
Answers
Answered by
GPT-4o mini
To demonstrate the Closure Property of multiplication of polynomials, we will find the product of the two given polynomials:
\((\frac{1}{2}x^2 - 3)(4y^3 + 5x^2).\)
We can distribute the terms as follows:
1. Multiply \(\frac{1}{2}x^2\) by each term in the second polynomial:
\[
\frac{1}{2}x^2 \cdot 4y^3 = 2x^2y^3,
\]
\[
\frac{1}{2}x^2 \cdot 5x^2 = \frac{5}{2}x^4.
\]
2. Multiply \(-3\) by each term in the second polynomial:
\[
-3 \cdot 4y^3 = -12y^3,
\]
\[
-3 \cdot 5x^2 = -15x^2.
\]
Now, combine all the results:
\[
2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2.
\]
Thus, the product is:
\[
\frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2.
\]
Now, we can review the options provided to find the matching answer:
- **A**. \(\frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2\) (This is correct)
- **B**. \(x^2y^3 + \frac{5}{x^4} - 8y^3 - 15x^2\) (Incorrect, since it incorrectly includes a division term)
- **C**. \(2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2\) (This is also correct, but the first term \(2x^2y^3\) appears odd compared to the usual expansion)
- **D**. \(\sqrt{x^2y^3} + 4x^4 - 15x^2\) (Incorrect, since it includes an erroneous square root and wrong coefficients)
Choice A matches our expansion accurately.
Thus, the final answer is **A**.
\((\frac{1}{2}x^2 - 3)(4y^3 + 5x^2).\)
We can distribute the terms as follows:
1. Multiply \(\frac{1}{2}x^2\) by each term in the second polynomial:
\[
\frac{1}{2}x^2 \cdot 4y^3 = 2x^2y^3,
\]
\[
\frac{1}{2}x^2 \cdot 5x^2 = \frac{5}{2}x^4.
\]
2. Multiply \(-3\) by each term in the second polynomial:
\[
-3 \cdot 4y^3 = -12y^3,
\]
\[
-3 \cdot 5x^2 = -15x^2.
\]
Now, combine all the results:
\[
2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2.
\]
Thus, the product is:
\[
\frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2.
\]
Now, we can review the options provided to find the matching answer:
- **A**. \(\frac{5}{2}x^4 + 2x^2y^3 - 12y^3 - 15x^2\) (This is correct)
- **B**. \(x^2y^3 + \frac{5}{x^4} - 8y^3 - 15x^2\) (Incorrect, since it incorrectly includes a division term)
- **C**. \(2x^2y^3 + \frac{5}{2}x^4 - 12y^3 - 15x^2\) (This is also correct, but the first term \(2x^2y^3\) appears odd compared to the usual expansion)
- **D**. \(\sqrt{x^2y^3} + 4x^4 - 15x^2\) (Incorrect, since it includes an erroneous square root and wrong coefficients)
Choice A matches our expansion accurately.
Thus, the final answer is **A**.
There are no human answers yet. A form for humans to post answers is coming very soon!