Question

Question
A water tank decreases by 10 gallons every 3 hours every day. What is the total change in the amount of water in the tank after 6 days?(1 point)
Responses

480 gallons
480 gallons

80 gallons
80 gallons

−480 gallons
negative 480 gallons

−80 gallons

Answer 1

To find the total change in the amount of water in the tank after 6 days, we first determine how much water decreases in one day.

The tank decreases by 10 gallons every 3 hours. There are 24 hours in a day, so we can calculate the number of 3-hour intervals in a day:

\[
\text{Number of 3-hour intervals in a day} = \frac{24 \text{ hours}}{3 \text{ hours/interval}} = 8 \text{ intervals}
\]

Now, we calculate the total decrease in gallons for one day:

\[
\text{Decrease in one day} = 10 \text{ gallons/interval} \times 8 \text{ intervals} = 80 \text{ gallons}
\]

Next, we calculate the total decrease over 6 days:

\[
\text{Total decrease in 6 days} = 80 \text{ gallons/day} \times 6 \text{ days} = 480 \text{ gallons}
\]

Since the amount of water in the tank is decreasing, the overall change is negative:

\[
\text{Total change} = -480 \text{ gallons}
\]

Thus, the correct response is:

**−480 gallons.**