Question

D #1 has 45 less molded veggies than d #2. D #2 has 80 less molded veggies than d#3. If there are 236 molded veggies in all of them combined, how many molded veggies are in d #1?

Answer 1

Let's denote the number of molded veggies in D#1 as \( x \), in D#2 as \( y \), and in D#3 as \( z \).

From the problem:
1. \( x = y - 45 \) (D#1 has 45 less molded veggies than D#2)
2. \( y = z - 80 \) (D#2 has 80 less molded veggies than D#3)
3. \( x + y + z = 236 \) (The total number of molded veggies is 236)

First, substitute \( y \) from the second equation into the first equation:

\[
x = (z - 80) - 45
\]
\[
x = z - 125
\]

Now substitute \( x \) and \( y \) into the total equation:

1. We already have \( y = z - 80 \).
2. We also have \( x = z - 125 \).

Now substituting both into the total:

\[
(z - 125) + (z - 80) + z = 236
\]

Combine like terms:

\[
3z - 205 = 236
\]

Now solve for \( z \):

\[
3z = 236 + 205
\]
\[
3z = 441
\]
\[
z = 147
\]

Now that we have \( z \), we can find \( y \):

\[
y = z - 80 = 147 - 80 = 67
\]

Now, find \( x \):

\[
x = y - 45 = 67 - 45 = 22
\]

So, D#1 has \( \boxed{22} \) molded veggies.

To check, calculate the total:

- D#1: 22
- D#2: 67
- D#3: 147

Adding these together:

\[
22 + 67 + 147 = 236
\]

The calculations are consistent. Thus, D#1 indeed has \( \boxed{22} \) molded veggies.