Question

2(2x-8)-8x (greater than <) 0

Answer 1

Let's solve the inequality \( 2(2x - 8) - 8x < 0 \).

1. Expand the left-hand side:
\[
2(2x - 8) = 4x - 16
\]
So the inequality becomes:
\[
4x - 16 - 8x < 0
\]

2. Combine like terms:
\[
4x - 8x - 16 < 0
\]
This simplifies to:
\[
-4x - 16 < 0
\]

3. Add 16 to both sides:
\[
-4x < 16
\]

4. Divide by -4 (remember to reverse the inequality sign):
\[
x > -4
\]

Thus, the solution to the inequality is:
\[
x > -4
\]