Let's go through the process of solving the Celsius to Fahrenheit formula \( F = \frac{9}{5}C + 32 \) for \( C \).
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Start with the given equation: \[ F = \frac{9}{5}C + 32 \]
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First step: Subtract 32 from both sides to isolate the term involving \( C \): \[ F - 32 = \frac{9}{5}C \]
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Now we have: \[ F - 32 = \frac{9}{5}C \]
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Next step: To eliminate the fraction, we can multiply both sides by \( \frac{5}{9} \): \[ \frac{5}{9}(F - 32) = C \]
Now let's check the options provided:
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A) First step is to multiply by 9 on each side.
- FALSE: The first step is to subtract 32, not multiply.
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B) First step is to add 32 to both sides.
- FALSE: The correct step is to subtract 32 from both sides.
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C) The next step from \( F - 32 = \frac{9}{5} C \), could be to multiply both sides by 5.
- FALSE: The correct way is to multiply both sides by \( \frac{5}{9} \) to isolate \( C \).
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D) The next step from \( F - 32 = \frac{9}{5} C \), could be to divide both sides by 5.
- FALSE: Dividing both sides by 5 would not correctly isolate \( C \); it should involve multiplying by \( \frac{5}{9} \).
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E) Solution: \( \frac{5}{9} F - 32 = C \).
- FALSE: The correct solution is \( C = \frac{5}{9}(F - 32) \), not \( \frac{5}{9} F - 32 \).
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F) To solve this equation for C, you would have to distribute at some point.
- FALSE: You do not need to distribute anything when isolating \( C \) since \( F - 32 \) is already grouped.
In summary, all options are FALSE.