The Celsius to Fahrenheit formula: F = 9 over 5C + 32

Let's go through the process of solving the Celsius to Fahrenheit formula \( F = \frac{9}{5}C + 32 \) for \( C \).

1. Start with the given equation:
\[
F = \frac{9}{5}C + 32
\]

2. **First step**: Subtract 32 from both sides to isolate the term involving \( C \):
\[
F - 32 = \frac{9}{5}C
\]

3. Now we have:
\[
F - 32 = \frac{9}{5}C
\]

4. **Next step**: To eliminate the fraction, we can multiply both sides by \( \frac{5}{9} \):
\[
\frac{5}{9}(F - 32) = C
\]

Now let's check the options provided:

- **A)** First step is to multiply by 9 on each side.
- **FALSE**: The first step is to subtract 32, not multiply.

- **B)** First step is to add 32 to both sides.
- **FALSE**: The correct step is to subtract 32 from both sides.

- **C)** The next step from \( F - 32 = \frac{9}{5} C \), could be to multiply both sides by 5.
- **FALSE**: The correct way is to multiply both sides by \( \frac{5}{9} \) to isolate \( C \).

- **D)** The next step from \( F - 32 = \frac{9}{5} C \), could be to divide both sides by 5.
- **FALSE**: Dividing both sides by 5 would not correctly isolate \( C \); it should involve multiplying by \( \frac{5}{9} \).

- **E)** Solution: \( \frac{5}{9} F - 32 = C \).
- **FALSE**: The correct solution is \( C = \frac{5}{9}(F - 32) \), not \( \frac{5}{9} F - 32 \).

- **F)** To solve this equation for C, you would have to distribute at some point.
- **FALSE**: You do not need to distribute anything when isolating \( C \) since \( F - 32 \) is already grouped.

In summary, all options are **FALSE**.