Subtract the polynomials. Indicate the degree of the resulting polynomial.

(6x^4y^2-9x^3y-8y) - (12x^4y^2x^3y+3y-12x)

(6x^4y^2-9x^3y-8y) - (12x^4y^2x^3y+3y-12x) = blank

The degree of the resulting polynomial is:

1 answer

Let's subtract the two polynomials step by step.

We start with the first polynomial: \[ (6x^4y^2 - 9x^3y - 8y) \]

Now we need to subtract the second polynomial: \[ (12x^4y^2 + 3y - 12x) \]

We can rewrite the subtraction as: \[ 6x^4y^2 - 9x^3y - 8y - (12x^4y^2 + 3y - 12x) \]

Distributing the negative sign to the second polynomial, we have: \[ 6x^4y^2 - 9x^3y - 8y - 12x^4y^2 - 3y + 12x \]

Now, we can combine like terms:

  1. For \(x^4y^2\): \[ 6x^4y^2 - 12x^4y^2 = -6x^4y^2 \]

  2. For \(x^3y\): \[ -9x^3y \quad (\text{there are no } x^3y \text{ terms to combine}) \]

  3. For \(y\): \[ -8y - 3y = -11y \]

  4. For \(x\): \[ +12x \quad (\text{there are no other } x \text{ terms to combine}) \]

Putting it all together, we have: \[ -6x^4y^2 - 9x^3y + 12x - 11y \]

Now, we can determine the degree of the resulting polynomial. The degree is the highest sum of the exponents of \(x\) and \(y\) in any term.

  1. The term \(-6x^4y^2\) has a degree of \(4 + 2 = 6\).
  2. The term \(-9x^3y\) has a degree of \(3 + 1 = 4\).
  3. The term \(12x\) has a degree of \(1\).
  4. The term \(-11y\) has a degree of \(1\).

The highest degree among the terms is \(6\).

Thus, the final result of the subtraction is: \[ -6x^4y^2 - 9x^3y + 12x - 11y \]

The degree of the resulting polynomial is: \[ \text{The degree of the resulting polynomial is: } 6 \]