Rationalize the denominator.

11/squareroot5-2

11/squareroot5-2= blank

1 answer

To rationalize the denominator of the expression \(\frac{11}{\sqrt{5} - 2}\), we can multiply the numerator and the denominator by the conjugate of the denominator, which is \(\sqrt{5} + 2\).

Here’s how we do it step by step:

\[ \frac{11}{\sqrt{5} - 2} \cdot \frac{\sqrt{5} + 2}{\sqrt{5} + 2} = \frac{11(\sqrt{5} + 2)}{(\sqrt{5} - 2)(\sqrt{5} + 2)} \]

Now, simplify the denominator:

\[ (\sqrt{5} - 2)(\sqrt{5} + 2) = \sqrt{5}^2 - 2^2 = 5 - 4 = 1 \]

Now substituting back, we have:

\[ \frac{11(\sqrt{5} + 2)}{1} = 11(\sqrt{5} + 2) \]

Thus, the rationalized form of the expression is:

\[ 11\sqrt{5} + 22 \]

So, the final answer is:

\[ \frac{11}{\sqrt{5} - 2} = 11\sqrt{5} + 22 \]