Question
A 2 kg object has a force of 10 N applied to it. What is the acceleration of the object?(2 points)
Responses
0.2 m/s²
0.2 m/s²
5 m/s²
5 m/s²
10 m/s²
10 m/s²
20 m/s²
Responses
0.2 m/s²
0.2 m/s²
5 m/s²
5 m/s²
10 m/s²
10 m/s²
20 m/s²
Answers
Answer
A spacecraft in deep space has engines that suddenly shut off, leaving it with no thrust. No other objects are nearby that can exert any gravitational force on the spacecraft. Which of the following statements best describes what will happen to the spacecraft's motion?(2 points)
Responses
It will gradually slow down and come to a stop.
It will gradually slow down and come to a stop.
It will change direction but maintain its speed.
It will change direction but maintain its speed.
It will continue moving in a straight line at a constant speed.
It will continue moving in a straight line at a constant speed.
It will gradually speed up due to
Responses
It will gradually slow down and come to a stop.
It will gradually slow down and come to a stop.
It will change direction but maintain its speed.
It will change direction but maintain its speed.
It will continue moving in a straight line at a constant speed.
It will continue moving in a straight line at a constant speed.
It will gradually speed up due to
Answer
A ball is dropped from a certain height and bounces back up. Considering Newton's Laws, which of the following best explains why the ball doesn't return to its original height?(2 points)
Responses
The First Law, because the ball remains at rest after hitting the ground.
The First Law, because the ball remains at rest after hitting the ground.
The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.
The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.
The Third Law, because the ground exerts a weaker force on the ball than the ball does on the ground.
The Third Law, because the ground exerts a weaker force on the ball than the ball does on the ground.
None of the above, because there is
Responses
The First Law, because the ball remains at rest after hitting the ground.
The First Law, because the ball remains at rest after hitting the ground.
The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.
The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.
The Third Law, because the ground exerts a weaker force on the ball than the ball does on the ground.
The Third Law, because the ground exerts a weaker force on the ball than the ball does on the ground.
None of the above, because there is
Answer
A swimmer pushes against the water to move forward. Which of the following best describes the forces involved according to Newton's Third Law?(2 points)
Responses
The water pushes back on the swimmer with less force.
The water pushes back on the swimmer with less force.
The swimmer's push and the water's push cancel each other out.
The swimmer's push and the water's push cancel each other out.
The water pushes back on the swimmer with an equal and opposite force.
The water pushes back on the swimmer with an equal and opposite force.
The swimmer moves because the force from the water is greater.
Responses
The water pushes back on the swimmer with less force.
The water pushes back on the swimmer with less force.
The swimmer's push and the water's push cancel each other out.
The swimmer's push and the water's push cancel each other out.
The water pushes back on the swimmer with an equal and opposite force.
The water pushes back on the swimmer with an equal and opposite force.
The swimmer moves because the force from the water is greater.
Answer
A student conducts an experiment applying different forces to a 3 kg object and records the following data:
Force (N) Acceleration (m/s 2)
5 1.67
10 3.33
15 5.00
If the student applies a force of 20 N to the object, what is the expected acceleration?
(2 points)
Responses
6.00 m/s 2
6.00 m/s 2
6.67 m/s 2
6.67 m/s 2
8.33 m/s 2
8.33 m/s 2
10.00 m/s 2
Force (N) Acceleration (m/s 2)
5 1.67
10 3.33
15 5.00
If the student applies a force of 20 N to the object, what is the expected acceleration?
(2 points)
Responses
6.00 m/s 2
6.00 m/s 2
6.67 m/s 2
6.67 m/s 2
8.33 m/s 2
8.33 m/s 2
10.00 m/s 2
Answered by
GPT-4o mini
To find the acceleration of the object, you can use Newton's second law of motion, which states that \( F = m \cdot a \), where \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration.
Given:
- Force \( F = 10 \, \text{N} \)
- Mass \( m = 2 \, \text{kg} \)
You can rearrange the formula to solve for acceleration \( a \):
\[
a = \frac{F}{m}
\]
Substituting the known values:
\[
a = \frac{10 \, \text{N}}{2 \, \text{kg}} = 5 \, \text{m/s}^2
\]
So, the acceleration of the object is **5 m/s²**.
Given:
- Force \( F = 10 \, \text{N} \)
- Mass \( m = 2 \, \text{kg} \)
You can rearrange the formula to solve for acceleration \( a \):
\[
a = \frac{F}{m}
\]
Substituting the known values:
\[
a = \frac{10 \, \text{N}}{2 \, \text{kg}} = 5 \, \text{m/s}^2
\]
So, the acceleration of the object is **5 m/s²**.
Answered by
GPT-4o mini
In deep space, if a spacecraft's engines suddenly shut off and there are no nearby objects exerting gravitational force, the spacecraft will not experience any external forces acting on it. According to Newton's first law of motion, an object in motion will continue in its state of motion (which includes both speed and direction) unless acted upon by an external force.
Given this situation, the correct statement is:
**It will continue moving in a straight line at a constant speed.**
Given this situation, the correct statement is:
**It will continue moving in a straight line at a constant speed.**
Answered by
GPT-4o mini
The best explanation for why the ball doesn't return to its original height after bouncing is:
**The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.**
When the ball hits the ground, some kinetic energy is converted into other forms of energy, such as thermal energy due to friction with the air and the surface of the ground. This energy loss means that not all the energy is available to propel the ball back to its original height, resulting in a lower bounce.
**The Second Law, because some energy is lost due to friction and air resistance after the force pushes it back up.**
When the ball hits the ground, some kinetic energy is converted into other forms of energy, such as thermal energy due to friction with the air and the surface of the ground. This energy loss means that not all the energy is available to propel the ball back to its original height, resulting in a lower bounce.
Answered by
GPT-4o mini
The best description of the forces involved when a swimmer pushes against the water, according to Newton's Third Law, is:
**The water pushes back on the swimmer with an equal and opposite force.**
According to Newton's Third Law, for every action, there is an equal and opposite reaction. When the swimmer pushes against the water, the water exerts an equal force in the opposite direction, propelling the swimmer forward.
**The water pushes back on the swimmer with an equal and opposite force.**
According to Newton's Third Law, for every action, there is an equal and opposite reaction. When the swimmer pushes against the water, the water exerts an equal force in the opposite direction, propelling the swimmer forward.
Answered by
GPT-4o mini
To find the expected acceleration when a force of 20 N is applied to a 3 kg object, we can use Newton's second law of motion, \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
From the previous data, we can calculate the acceleration for various forces, and we see a linear relationship. Let's use one of the recorded forces to find the constant of proportionality:
1. For a force of 5 N, the acceleration is 1.67 m/s²:
\[
a = \frac{F}{m} \implies 1.67 = \frac{5}{3} \implies F = m \cdot a \implies F = 3 \cdot 1.67 = 5
\]
2. For a force of 10 N, the acceleration is 3.33 m/s²:
\[
a = \frac{F}{m} \implies 3.33 = \frac{10}{3} \implies 3.33 \cdot 3 = 10
\]
3. For a force of 15 N, the acceleration is 5.00 m/s²:
\[
a = \frac{F}{m} \implies 5.00 = \frac{15}{3} \implies 5 = \frac{15}{3}
\]
From this, we can confirm that the acceleration is calculated correctly with the known mass of 3 kg and the applied forces.
Now we can calculate the acceleration for a force of 20 N:
\[
a = \frac{F}{m} = \frac{20 \, \text{N}}{3 \, \text{kg}} \approx 6.67 \, \text{m/s}^2
\]
Thus, the expected acceleration when a force of 20 N is applied to the object is **6.67 m/s²**.
From the previous data, we can calculate the acceleration for various forces, and we see a linear relationship. Let's use one of the recorded forces to find the constant of proportionality:
1. For a force of 5 N, the acceleration is 1.67 m/s²:
\[
a = \frac{F}{m} \implies 1.67 = \frac{5}{3} \implies F = m \cdot a \implies F = 3 \cdot 1.67 = 5
\]
2. For a force of 10 N, the acceleration is 3.33 m/s²:
\[
a = \frac{F}{m} \implies 3.33 = \frac{10}{3} \implies 3.33 \cdot 3 = 10
\]
3. For a force of 15 N, the acceleration is 5.00 m/s²:
\[
a = \frac{F}{m} \implies 5.00 = \frac{15}{3} \implies 5 = \frac{15}{3}
\]
From this, we can confirm that the acceleration is calculated correctly with the known mass of 3 kg and the applied forces.
Now we can calculate the acceleration for a force of 20 N:
\[
a = \frac{F}{m} = \frac{20 \, \text{N}}{3 \, \text{kg}} \approx 6.67 \, \text{m/s}^2
\]
Thus, the expected acceleration when a force of 20 N is applied to the object is **6.67 m/s²**.
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