Add the polynomial expressions 2r^2 − 3r + 4 and −2r^2 + 3r + 6.

Question

(1 point)

Answer 1

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), we simply combine like terms:

1. Combine the \(r^2\) terms: \[ 2r^2 + (-2r^2) = 0r^2 \]

2. Combine the \(r\) terms: \[ -3r + 3r = 0r \]

3. Combine the constant terms: \[ 4 + 6 = 10 \]

Putting it all together: \[ 0r^2 + 0r + 10 = 10 \]

So, the sum of the given polynomial expressions is: \[ \boxed{10} \]