Which of these potential solutions make the equation x2+9=0 true?

1 answer

To solve the equation \( x^2 + 9 = 0 \), we can start by isolating \( x^2 \):

\[ x^2 = -9 \]

Next, we take the square root of both sides:

\[ x = \pm \sqrt{-9} \]

Since the square root of a negative number involves imaginary numbers, we can express this as:

\[ x = \pm 3i \]

Thus, the solutions to the equation \( x^2 + 9 = 0 \) are:

\[ x = 3i \quad \text{and} \quad x = -3i \]

These are the values that make the equation true.