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how do i evaluate this limit:
lim x tends to 5 x-3-2x^2/1+3x
7 answers
The denominator (1 + 3x) does not vanish when x=5. So, just evaluate the function at x = 5.
ok lemme write it over then:
How do i find the lim x-->5 (x-3-2x^2)/(1+3x)
How do i find the lim x-->5 (x-3-2x^2)/(1+3x)
so drwls do i have to change the top into something similar or just plug in x=5 into the entire equation.
sorry i mean the top looks like a quadratic do i break it down or just leave it as it is and just plug in x=5 into the entire equation?
oh don't worry drwls, i now understand. thanks!
you take the evaluated equation and you lose all similar sines by xsing. onse you are left with a group of different signs you square all them and then do the problem. once you have the answer you take the square root of that and then times it by 2^
drwls don't know what he is talking about
drwls don't know what he is talking about
0 answers