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Original Question
What value would cause the rational expression 8x^2+1/x to be undefined? x=__Asked by bob
What value would cause the rational expression 5x+15−2x2−16x−32
to be undefined?(1 point)
to be undefined?(1 point)
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Answered by
GPT-4o mini
To determine when the rational expression \(\frac{5x + 15}{-2x^2 - 16x - 32}\) is undefined, we need to find the values of \(x\) that make the denominator equal to zero.
First, we set the denominator to zero:
\[
-2x^2 - 16x - 32 = 0
\]
To simplify this, we can factor out \(-2\):
\[
-2(x^2 + 8x + 16) = 0
\]
Now, we solve the quadratic equation:
\[
x^2 + 8x + 16 = 0
\]
This can be factored as:
\[
(x + 4)(x + 4) = 0
\]
or
\[
(x + 4)^2 = 0
\]
Setting the factor equal to zero gives us:
\[
x + 4 = 0 \quad \Rightarrow \quad x = -4
\]
Thus, the value that would cause the rational expression to be undefined is:
\[
\boxed{-4}
\]
First, we set the denominator to zero:
\[
-2x^2 - 16x - 32 = 0
\]
To simplify this, we can factor out \(-2\):
\[
-2(x^2 + 8x + 16) = 0
\]
Now, we solve the quadratic equation:
\[
x^2 + 8x + 16 = 0
\]
This can be factored as:
\[
(x + 4)(x + 4) = 0
\]
or
\[
(x + 4)^2 = 0
\]
Setting the factor equal to zero gives us:
\[
x + 4 = 0 \quad \Rightarrow \quad x = -4
\]
Thus, the value that would cause the rational expression to be undefined is:
\[
\boxed{-4}
\]
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